Question 1
Link to questionConsider a web application where a developer is implementing a feature to process user input asynchronously. A function named `processData` is defined, which initializes a variable `dataValue` to `10` using the `let` keyword. Inside `processData`, a `setTimeout` function is called with a delay of 0 milliseconds, and its callback attempts to log the value of `dataValue`. Immediately after the `setTimeout` call, but before the callback is executed, `dataValue` is reassigned to `50`. What will be the output logged to the console when this code snippet is executed?
50
10
Undefined
An error will occur
Show answer and explanation
Correct answer
50
The core of this question lies in understanding how JavaScript handles variable scope and the implications of the `let` keyword. When `processData` is called, a new execution context is created. Inside this context, `let` declares `dataValue` within the function\'s block scope. When the `setTimeout` callback executes, it captures the `dataValue` from its surrounding scope at the time of creation. Since `dataValue` is reassigned to `50` before the `setTimeout` callback fires, the callback will reference this updated value. The initial value of `dataValue` (which was `10`) is not directly accessible by the `setTimeout` callback once `dataValue` has been reassigned within the same scope. Therefore, the callback will log the most recently assigned value, which is `50`. This demonstrates the concept of closures and how they capture variables by reference, not by value, in the case of `let` and `var` in modern JavaScript. Understanding this behavior is crucial for predictable asynchronous operations and avoiding unexpected side effects in applications.
